Imagine the length of a 10Base5 cable is 2500 meters. If the speed of propagation in a thick coaxial cable is 200,000,000 meters/second, how long does it take for a bit to travel from the beginning to the end of the network?

Question

Ignore any propagation delay in the equipment.

Answer 1

We know that D = T × V, where D is the distance, T is the time, and V is the velocity or speed. 

In other words, T = D / V. We insert the corresponding values to find the time needed for a bit to travel the cable.

T = D / V = (2500 meters) / (200,000,000 meters/second) = 0.0000125 s = 12.5 μs