Assume that the minimum frame size is **65 bytes **or** 520 bits**. We have** L = T × R**, where **L** is the length of the frame, **T** is the time, and the **R **is the data rate. We can say **T = L / R**. The time can be calculated as

**T = L / R** = (520 bits) / (10,000,000) bits/second = 0.000052 s = **52 μs.**