# How many hexadecimal digits are needed to define the netid in each of the following classes?

931 views a. Class A

b. Class B

c. Class C

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selected by (user.guest)

a. (8 bits) / (4 bits per hex digits) = 2 hex digits

b. (16 bits) / (4 bits per hex digits) = 4 hex digits

c. (24 bits) / (4 bits per hex digits) = 6 hex digits by
sorry have a question
how can you do to gate the answer
by (user.guest)
In a class A address, you need to know that 1 byte (8bits) is used to represent the netid part of the address. Since 1 hex digit = 4 bits, 8 bits will be 2 hex digits.

In a class B address, 2 bytes (16 bits) is used to represent the netid part of the address. Since 1 hex digit = 4 bits, 16 bits will be 4 hex digits.

In a class C address, 3 bytes (24 bits) is used to represent the netid part of the address. Since 1 hex digit = 4 bits, 24 bits will be 6 hex digits.

For more clarity on how the netids are derived, see the question on finding netid from addresses here > https://cpentalk.com/1533/find-the-netid-and-the-hostid-of-the-following-ip-addresses

You might want to checkout some really helpful computer network books here > https://cpentalk.com/drive

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