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a. 255.255.255.0

b. 255.0.0.0

c. 255.255.224.0

d. 255.255.240.0

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We first change the mask to binary to find the number of 1’s:

a. 11111111 11111111 11111111 00000000/24

b. 11111111 00000000 00000000 00000000 /8

c. 11111111 11111111 11100000 00000000 /19

d. 11111111 11111111 11110000 00000000 /20

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