**Step 1:** Consider the constraints variable F and it shows that it can only take the value 1. Thus, the variable (broken image) can caries 0 or 1 and according to condition (broken image). Therefore, (broken image)=1.

(broken image)

**Step 2:** Now, after F = 1, is consider that the rest variable U, W, R, O may have the value 0 to 9.

Thus, the value T is not to be zero and one, so T may be one of {2, 3, 4, 5, 6, 7, 8, 9}.

According to the MRV heuristic constraints the state is:

(broken image)

Therefore, consider that the assigning values two, three, four values to T, then no possible values for O. If assign the 5 to T, then the single value of O is zero. Now, consider the rest value {6, 7, 8} value to assign the value to T. Here, applies the least constraining heuristic approach to choose the value for T.

Therefore, the value of T is 6.

(broken image)

**Step 3**: According to the step 2 (broken image). Therefore, the (broken image) caries either 0 or 1. Thus, the value of O is may be {2,3}. Now, applies the applies the least constraining heuristic approach to choose the value for O.

Hence, the value of O is 2.

(broken image)

**Step 4:** Now, find the value for constraints R. Consider the statement:

(broken image)

Consider that (broken image) either 0 or 1. So, (broken image) is zero because R is not to be negative.

Hence, R = 4.

(broken image)