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Solution:

Here n= 20: p=10/100 =0.1: q=0.9;

By binomial distribution,the probability of getting x defective bulbs

a)probability of getting all good bulbs = probability of getting zero

defective bulbs.

=p(x=0)

=(0.9)20

b)p(x<=3)=p(x=0)+p(x=1)+p(x=2)+p(x=3)

=.8671

c)p(x=3)=.1901

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