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In order to keep the pipe full, the window should be able to open to Bandwidth*RTT / 8 = 100Mbps * 200msec/8 = 2.5MBytes. Therefore the window should have log22.5M = 22 bits.

During a 150 second interval the source can transmit up to 150sec *100Mbps/8 = 1.875 GB, which requires 31 bits.

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